Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …101110000011011001111110 |
3 | 122002211102002200121220112002 |
4 | 131222010202232003121332 |
5 | 114044014220220411032 |
6 | 1141224431223142302 |
7 | 36321402060335660 |
oct | 3552044256033176 |
9 | 562742080556462 |
10 | 130434444310142 |
11 | 38618a34437645 |
12 | 1276709b5a4992 |
13 | 57a1bb8c63c1b |
14 | 242d0bcb3a530 |
15 | 1012d74d58862 |
hex | 76a122b8367e |
130434444310142 has 16 divisors (see below), whose sum is σ = 230814869194752. Its totient is φ = 54097234967160.
The previous prime is 130434444310141. The next prime is 130434444310147. The reversal of 130434444310142 is 241013444434031.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 130434444310096 and 130434444310105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130434444310141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150270096698 + ... + 150270097565.
It is an arithmetic number, because the mean of its divisors is an integer number (14425929324672).
Almost surely, 2130434444310142 is an apocalyptic number.
130434444310142 is a deficient number, since it is larger than the sum of its proper divisors (100380424884610).
130434444310142 is a wasteful number, since it uses less digits than its factorization.
130434444310142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 300540194303.
The product of its (nonzero) digits is 221184, while the sum is 38.
Adding to 130434444310142 its reverse (241013444434031), we get a palindrome (371447888744173).
The spelling of 130434444310142 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred forty-four million, three hundred ten thousand, one hundred forty-two".
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