130440000000421 has 2 divisors, whose sum is σ = 130440000000422. Its totient is φ = 130440000000420.

The previous prime is 130440000000403. The next prime is 130440000000439. The reversal of 130440000000421 is 124000000044031.

It is a balanced prime because it is at equal distance from previous prime (130440000000403) and next prime (130440000000439).

It can be written as a sum of positive squares in only one way, i.e., 98942212180900 + 31497787819521 = 9946970^2 + 5612289^2 .

It is a cyclic number.

It is not a de Polignac number, because 130440000000421 - 2⁷ = 130440000000293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130440000003421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220000000210 + 65220000000211.

It is an arithmetic number, because the mean of its divisors is an integer number (65220000000211).

Almost surely, 2^{130440000000421} is an apocalyptic number.

It is an amenable number.

130440000000421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130440000000421 is an equidigital number, since it uses as much as digits as its factorization.

130440000000421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 130440000000421 its reverse (124000000044031), we get a palindrome (254440000044452).

The spelling of 130440000000421 in words is "one hundred thirty trillion, four hundred forty billion, four hundred twenty-one", and thus it is an aban number.