Base | Representation |
---|---|
bin | 10010111110110100011… |
… | …011010100001001100011 |
3 | 11121200220000202211202021 |
4 | 102332310123110021203 |
5 | 132332403422244422 |
6 | 2435122321002311 |
7 | 163145205223036 |
oct | 22766433241143 |
9 | 4550800684667 |
10 | 1304402149987 |
11 | 46321500a682 |
12 | 190975783397 |
13 | 9600a130c11 |
14 | 471c20a301d |
15 | 23de5635dc7 |
hex | 12fb46d4263 |
1304402149987 has 2 divisors, whose sum is σ = 1304402149988. Its totient is φ = 1304402149986.
The previous prime is 1304402149943. The next prime is 1304402149997. The reversal of 1304402149987 is 7899412044031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304402149987 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304402149997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652201074993 + 652201074994.
It is an arithmetic number, because the mean of its divisors is an integer number (652201074994).
Almost surely, 21304402149987 is an apocalyptic number.
1304402149987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304402149987 is an equidigital number, since it uses as much as digits as its factorization.
1304402149987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1741824, while the sum is 52.
The spelling of 1304402149987 in words is "one trillion, three hundred four billion, four hundred two million, one hundred forty-nine thousand, nine hundred eighty-seven".
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