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130440231114044 = 22271928229424861
BaseRepresentation
bin11101101010001001111011…
…101000111101010100111100
3122002211222000222112000010112
4131222021323220331110330
5114044113043131122134
61141231225342325152
736321665345346245
oct3552117350752474
9562758028460115
10130440231114044
1138620433992005
12127682355897b8
1357a25cbb05147
14242d4ab4cdccc
1510130b2dcc1ce
hex76a27ba3d53c

130440231114044 has 24 divisors (see below), whose sum is σ = 228362985110400. Its totient is φ = 65193665762880.

The previous prime is 130440231114031. The next prime is 130440231114091. The reversal of 130440231114044 is 440411132044031.

It is a self number, because there is not a number n which added to its sum of digits gives 130440231114044.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 306806174 + ... + 307231034.

It is an arithmetic number, because the mean of its divisors is an integer number (9515124379600).

Almost surely, 2130440231114044 is an apocalyptic number.

It is an amenable number.

130440231114044 is a deficient number, since it is larger than the sum of its proper divisors (97922753996356).

130440231114044 is a wasteful number, since it uses less digits than its factorization.

130440231114044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455813 (or 455811 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 130440231114044 its reverse (440411132044031), we get a palindrome (570851363158075).

The spelling of 130440231114044 in words is "one hundred thirty trillion, four hundred forty billion, two hundred thirty-one million, one hundred fourteen thousand, forty-four".

Divisors: 1 2 4 2719 5438 10876 28229 56458 112916 424861 849722 1699444 76754651 153509302 307018604 1155197059 2310394118 4620788236 11993401169 23986802338 47973604676 32610057778511 65220115557022 130440231114044