Base | Representation |
---|---|
bin | 10010111110110100100… |
… | …011111001111101110111 |
3 | 11121200220012000020222121 |
4 | 102332310203321331313 |
5 | 132332410011331124 |
6 | 2435122441140411 |
7 | 163145233322554 |
oct | 22766443717567 |
9 | 4550805006877 |
10 | 1304404402039 |
11 | 463216308682 |
12 | 19097648a707 |
13 | 9600a73bcab |
14 | 471c24cba2b |
15 | 23de592d2e4 |
hex | 12fb48f9f77 |
1304404402039 has 2 divisors, whose sum is σ = 1304404402040. Its totient is φ = 1304404402038.
The previous prime is 1304404401991. The next prime is 1304404402043. The reversal of 1304404402039 is 9302044044031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304404402039 is a prime.
It is a super-2 number, since 2×13044044020392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1304404401995 and 1304404402013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304405402039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652202201019 + 652202201020.
It is an arithmetic number, because the mean of its divisors is an integer number (652202201020).
Almost surely, 21304404402039 is an apocalyptic number.
1304404402039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304404402039 is an equidigital number, since it uses as much as digits as its factorization.
1304404402039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
The spelling of 1304404402039 in words is "one trillion, three hundred four billion, four hundred four million, four hundred two thousand, thirty-nine".
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