Base | Representation |
---|---|
bin | 11101101010001010101010… |
… | …101010010110111110110111 |
3 | 122002212001001221222002111221 |
4 | 131222022222222112332313 |
5 | 114044121202110313143 |
6 | 1141231435523211211 |
7 | 36322024035015553 |
oct | 3552125252267667 |
9 | 562761057862457 |
10 | 130441020010423 |
11 | 386207a9229591 |
12 | 12768415816b07 |
13 | 57a26c639b035 |
14 | 242d5441a8863 |
15 | 101310c2ae2ed |
hex | 76a2aaa96fb7 |
130441020010423 has 2 divisors, whose sum is σ = 130441020010424. Its totient is φ = 130441020010422.
The previous prime is 130441020010381. The next prime is 130441020010439. The reversal of 130441020010423 is 324010020144031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130441020010423 - 213 = 130441020002231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130441020010463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220510005211 + 65220510005212.
It is an arithmetic number, because the mean of its divisors is an integer number (65220510005212).
Almost surely, 2130441020010423 is an apocalyptic number.
130441020010423 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441020010423 is an equidigital number, since it uses as much as digits as its factorization.
130441020010423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 130441020010423 its reverse (324010020144031), we get a palindrome (454451040154454).
The spelling of 130441020010423 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, ten thousand, four hundred twenty-three".
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