130441020024340 has 24 divisors (see below), whose sum is σ = 275345448494760. Its totient is φ = 51906063925248.

The previous prime is 130441020024319. The next prime is 130441020024377. The reversal of 130441020024340 is 43420020144031.

It can be written as a sum of positive squares in 4 ways, for example, as 944904531844 + 129496115492496 = 972062^2 + 11379636^2 .

It is a super-3 number, since 3×130441020024340³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130441020024299 and 130441020024308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16896501325 + ... + 16896509044.

It is an arithmetic number, because the mean of its divisors is an integer number (11472727020615).

Almost surely, 2^{130441020024340} is an apocalyptic number.

130441020024340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130441020024340 is an abundant number, since it is smaller than the sum of its proper divisors (144904428470420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130441020024340 is a wasteful number, since it uses less digits than its factorization.

130441020024340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33793010571 (or 33793010569 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 130441020024340 its reverse (43420020144031), we get a palindrome (173861040168371).

The spelling of 130441020024340 in words is "one hundred thirty trillion, four hundred forty-one billion, twenty million, twenty-four thousand, three hundred forty".