Base | Representation |
---|---|
bin | 11101101010001010101011… |
… | …010001111111100110010111 |
3 | 122002212001002200111221220011 |
4 | 131222022223101333212113 |
5 | 114044121212240303112 |
6 | 1141231440534021051 |
7 | 36322024222231216 |
oct | 3552125321774627 |
9 | 562761080457804 |
10 | 130441030400407 |
11 | 38620804085751 |
12 | 127684191a7787 |
13 | 57a26c859825c |
14 | 242d54571107d |
15 | 101310d162aa7 |
hex | 76a2ab47f997 |
130441030400407 has 2 divisors, whose sum is σ = 130441030400408. Its totient is φ = 130441030400406.
The previous prime is 130441030400363. The next prime is 130441030400431. The reversal of 130441030400407 is 704004030144031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130441030400407 - 27 = 130441030400279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130441030400467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515200203 + 65220515200204.
It is an arithmetic number, because the mean of its divisors is an integer number (65220515200204).
Almost surely, 2130441030400407 is an apocalyptic number.
130441030400407 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441030400407 is an equidigital number, since it uses as much as digits as its factorization.
130441030400407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 130441030400407 its reverse (704004030144031), we get a palindrome (834445060544438).
The spelling of 130441030400407 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty million, four hundred thousand, four hundred seven".
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