Search a number
-
+
130441030414333 is a prime number
BaseRepresentation
bin11101101010001010101011…
…010010000010111111111101
3122002212001002200112122222221
4131222022223102002333331
5114044121212241224313
61141231440534205341
736322024222316632
oct3552125322027775
9562761080478887
10130441030414333
1138620804095161
12127684191b3851
1357a26c85a16b2
14242d545716189
15101310d166c8d
hex76a2ab482ffd

130441030414333 has 2 divisors, whose sum is σ = 130441030414334. Its totient is φ = 130441030414332.

The previous prime is 130441030414259. The next prime is 130441030414369. The reversal of 130441030414333 is 333414030144031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130189309462809 + 251720951524 = 11410053^2 + 501718^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130441030414333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441030414733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515207166 + 65220515207167.

It is an arithmetic number, because the mean of its divisors is an integer number (65220515207167).

Almost surely, 2130441030414333 is an apocalyptic number.

It is an amenable number.

130441030414333 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441030414333 is an equidigital number, since it uses as much as digits as its factorization.

130441030414333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 130441030414333 its reverse (333414030144031), we get a palindrome (463855060558364).

The spelling of 130441030414333 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty million, four hundred fourteen thousand, three hundred thirty-three".