Base | Representation |
---|---|
bin | 11101101010001010101011… |
… | …010010000010111111111101 |
3 | 122002212001002200112122222221 |
4 | 131222022223102002333331 |
5 | 114044121212241224313 |
6 | 1141231440534205341 |
7 | 36322024222316632 |
oct | 3552125322027775 |
9 | 562761080478887 |
10 | 130441030414333 |
11 | 38620804095161 |
12 | 127684191b3851 |
13 | 57a26c85a16b2 |
14 | 242d545716189 |
15 | 101310d166c8d |
hex | 76a2ab482ffd |
130441030414333 has 2 divisors, whose sum is σ = 130441030414334. Its totient is φ = 130441030414332.
The previous prime is 130441030414259. The next prime is 130441030414369. The reversal of 130441030414333 is 333414030144031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130189309462809 + 251720951524 = 11410053^2 + 501718^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130441030414333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130441030414733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220515207166 + 65220515207167.
It is an arithmetic number, because the mean of its divisors is an integer number (65220515207167).
Almost surely, 2130441030414333 is an apocalyptic number.
It is an amenable number.
130441030414333 is a deficient number, since it is larger than the sum of its proper divisors (1).
130441030414333 is an equidigital number, since it uses as much as digits as its factorization.
130441030414333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 130441030414333 its reverse (333414030144031), we get a palindrome (463855060558364).
The spelling of 130441030414333 in words is "one hundred thirty trillion, four hundred forty-one billion, thirty million, four hundred fourteen thousand, three hundred thirty-three".
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