Base | Representation |
---|---|
bin | 11101101010001010110000… |
… | …000101011101110011001000 |
3 | 122002212001022022011221220220 |
4 | 131222022300011131303020 |
5 | 114044121343404033222 |
6 | 1141231452533350040 |
7 | 36322026221312205 |
oct | 3552126005356310 |
9 | 562761268157826 |
10 | 130441111002312 |
11 | 386208456280a0 |
12 | 12768440198320 |
13 | 57a270c1a95a6 |
14 | 242d5522d2cac |
15 | 1013115284b5c |
hex | 76a2b015dcc8 |
130441111002312 has 128 divisors (see below), whose sum is σ = 356716857744000. Its totient is φ = 39420043120640.
The previous prime is 130441111002199. The next prime is 130441111002313. The reversal of 130441111002312 is 213200111144031.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (130441111002313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 705326368 + ... + 705511280.
It is an arithmetic number, because the mean of its divisors is an integer number (2786850451125).
Almost surely, 2130441111002312 is an apocalyptic number.
130441111002312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130441111002312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178358428872000).
130441111002312 is an abundant number, since it is smaller than the sum of its proper divisors (226275746741688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130441111002312 is a wasteful number, since it uses less digits than its factorization.
130441111002312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192191 (or 192187 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 130441111002312 its reverse (213200111144031), we get a palindrome (343641222146343).
The spelling of 130441111002312 in words is "one hundred thirty trillion, four hundred forty-one billion, one hundred eleven million, two thousand, three hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •