Base | Representation |
---|---|
bin | 10010111110110101000… |
… | …101000111111011101111 |
3 | 11121200220210101200001122 |
4 | 102332311011013323233 |
5 | 132332414224004444 |
6 | 2435123351531155 |
7 | 163145400331316 |
oct | 22766505077357 |
9 | 4550823350048 |
10 | 1304413109999 |
11 | 46322021603a |
12 | 190979389abb |
13 | 9600c49a72c |
14 | 471c371727d |
15 | 23de659d4ee |
hex | 12fb5147eef |
1304413109999 has 2 divisors, whose sum is σ = 1304413110000. Its totient is φ = 1304413109998.
The previous prime is 1304413109933. The next prime is 1304413110041. The reversal of 1304413109999 is 9999013144031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1304413109999 - 232 = 1300118142703 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1304413109999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304413100999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652206554999 + 652206555000.
It is an arithmetic number, because the mean of its divisors is an integer number (652206555000).
Almost surely, 21304413109999 is an apocalyptic number.
1304413109999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304413109999 is an equidigital number, since it uses as much as digits as its factorization.
1304413109999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 944784, while the sum is 53.
The spelling of 1304413109999 in words is "one trillion, three hundred four billion, four hundred thirteen million, one hundred nine thousand, nine hundred ninety-nine".
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