130441410203341 has 2 divisors, whose sum is σ = 130441410203342. Its totient is φ = 130441410203340.

The previous prime is 130441410203339. The next prime is 130441410203411. The reversal of 130441410203341 is 143302014144031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100191091202500 + 30250319000841 = 10009550^2 + 5500029^2 .

It is a cyclic number.

It is not a de Polignac number, because 130441410203341 - 2¹ = 130441410203339 is a prime.

It is a super-4 number, since 4×130441410203341⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 130441410203339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130441410203311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220705101670 + 65220705101671.

It is an arithmetic number, because the mean of its divisors is an integer number (65220705101671).

Almost surely, 2^{130441410203341} is an apocalyptic number.

It is an amenable number.

130441410203341 is a deficient number, since it is larger than the sum of its proper divisors (1).

130441410203341 is an equidigital number, since it uses as much as digits as its factorization.

130441410203341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 130441410203341 its reverse (143302014144031), we get a palindrome (273743424347372).

The spelling of 130441410203341 in words is "one hundred thirty trillion, four hundred forty-one billion, four hundred ten million, two hundred three thousand, three hundred forty-one".