13044142123 has 2 divisors, whose sum is σ = 13044142124. Its totient is φ = 13044142122.

The previous prime is 13044142121. The next prime is 13044142127. The reversal of 13044142123 is 32124144031.

13044142123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13044142123 - 2¹ = 13044142121 is a prime.

Together with 13044142121, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13044142121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522071061 + 6522071062.

It is an arithmetic number, because the mean of its divisors is an integer number (6522071062).

Almost surely, 2^13044142123 is an apocalyptic number.

13044142123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044142123 is an equidigital number, since it uses as much as digits as its factorization.

13044142123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13044142123 its reverse (32124144031), we get a palindrome (45168286154).

The spelling of 13044142123 in words is "thirteen billion, forty-four million, one hundred forty-two thousand, one hundred twenty-three".