Base | Representation |
---|---|
bin | 100110110111111… |
… | …1101111100010000 |
3 | 10100220111102000000 |
4 | 1031233331330100 |
5 | 10132412420422 |
6 | 333234130000 |
7 | 44216250042 |
oct | 11557757420 |
9 | 3326442000 |
10 | 1304420112 |
11 | 60a347156 |
12 | 304a20900 |
13 | 17a324b28 |
14 | c5351a92 |
15 | 797b4cac |
hex | 4dbfdf10 |
1304420112 has 70 divisors (see below), whose sum is σ = 3789271422. Its totient is φ = 434802816.
The previous prime is 1304420111. The next prime is 1304420123. The reversal of 1304420112 is 2110244031.
1304420112 is a `hidden beast` number, since 130 + 4 + 420 + 112 = 666.
It can be written as a sum of positive squares in only one way, i.e., 994519296 + 309900816 = 31536^2 + 17604^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304420111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 44253 + ... + 67580.
Almost surely, 21304420112 is an apocalyptic number.
1304420112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1304420112 is an abundant number, since it is smaller than the sum of its proper divisors (2484851310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304420112 is an equidigital number, since it uses as much as digits as its factorization.
1304420112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 111859 (or 111838 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
The square root of 1304420112 is about 36116.7566650163. The cubic root of 1304420112 is about 1092.6284270754.
Adding to 1304420112 its reverse (2110244031), we get a palindrome (3414664143).
The spelling of 1304420112 in words is "one billion, three hundred four million, four hundred twenty thousand, one hundred twelve".
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