Base | Representation |
---|---|
bin | 11101101010001011101011… |
… | …110000001000100100100110 |
3 | 122002212010220001211010000010 |
4 | 131222023223300020210212 |
5 | 114044130421140341202 |
6 | 1141232140133231050 |
7 | 36322063065110103 |
oct | 3552135360104446 |
9 | 562763801733003 |
10 | 130442112043302 |
11 | 386212096a1aa4 |
12 | 1276867b492486 |
13 | 57a283b6bc537 |
14 | 242d609231aaa |
15 | 10131730be76c |
hex | 76a2ebc08926 |
130442112043302 has 32 divisors (see below), whose sum is σ = 262645453778400. Its totient is φ = 43187188686080.
The previous prime is 130442112043301. The next prime is 130442112043307. The reversal of 130442112043302 is 203340211244031.
It is a self number, because there is not a number n which added to its sum of digits gives 130442112043302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130442112043301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19977298 + ... + 25690010.
It is an arithmetic number, because the mean of its divisors is an integer number (8207670430575).
Almost surely, 2130442112043302 is an apocalyptic number.
130442112043302 is an abundant number, since it is smaller than the sum of its proper divisors (132203341735098).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130442112043302 is a wasteful number, since it uses less digits than its factorization.
130442112043302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5738408.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 130442112043302 its reverse (203340211244031), we get a palindrome (333782323287333).
The spelling of 130442112043302 in words is "one hundred thirty trillion, four hundred forty-two billion, one hundred twelve million, forty-three thousand, three hundred two".
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