Base | Representation |
---|---|
bin | 111100101111011110… |
… | …1101010000000110101 |
3 | 110110200202002100221001 |
4 | 1321132331222000311 |
5 | 4114121203140203 |
6 | 135531353523301 |
7 | 12265323513646 |
oct | 1713675520065 |
9 | 413622070831 |
10 | 130442240053 |
11 | 50358275684 |
12 | 21344a13531 |
13 | c3ba6b5438 |
14 | 64561076cd |
15 | 35d6abc91d |
hex | 1e5ef6a035 |
130442240053 has 2 divisors, whose sum is σ = 130442240054. Its totient is φ = 130442240052.
The previous prime is 130442239973. The next prime is 130442240057. The reversal of 130442240053 is 350042244031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128810645604 + 1631594449 = 358902^2 + 40393^2 .
It is an emirp because it is prime and its reverse (350042244031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130442240053 - 217 = 130442108981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130442240057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221120026 + 65221120027.
It is an arithmetic number, because the mean of its divisors is an integer number (65221120027).
Almost surely, 2130442240053 is an apocalyptic number.
It is an amenable number.
130442240053 is a deficient number, since it is larger than the sum of its proper divisors (1).
130442240053 is an equidigital number, since it uses as much as digits as its factorization.
130442240053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 28.
Adding to 130442240053 its reverse (350042244031), we get a palindrome (480484484084).
The spelling of 130442240053 in words is "one hundred thirty billion, four hundred forty-two million, two hundred forty thousand, fifty-three".
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