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130442240053 is a prime number
BaseRepresentation
bin111100101111011110…
…1101010000000110101
3110110200202002100221001
41321132331222000311
54114121203140203
6135531353523301
712265323513646
oct1713675520065
9413622070831
10130442240053
1150358275684
1221344a13531
13c3ba6b5438
1464561076cd
1535d6abc91d
hex1e5ef6a035

130442240053 has 2 divisors, whose sum is σ = 130442240054. Its totient is φ = 130442240052.

The previous prime is 130442239973. The next prime is 130442240057. The reversal of 130442240053 is 350042244031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128810645604 + 1631594449 = 358902^2 + 40393^2 .

It is an emirp because it is prime and its reverse (350042244031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130442240053 - 217 = 130442108981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130442240057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221120026 + 65221120027.

It is an arithmetic number, because the mean of its divisors is an integer number (65221120027).

Almost surely, 2130442240053 is an apocalyptic number.

It is an amenable number.

130442240053 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442240053 is an equidigital number, since it uses as much as digits as its factorization.

130442240053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 130442240053 its reverse (350042244031), we get a palindrome (480484484084).

The spelling of 130442240053 in words is "one hundred thirty billion, four hundred forty-two million, two hundred forty thousand, fifty-three".