13044241011301 has 2 divisors, whose sum is σ = 13044241011302. Its totient is φ = 13044241011300.

The previous prime is 13044241011293. The next prime is 13044241011337. The reversal of 13044241011301 is 10311014244031.

13044241011301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7114889390625 + 5929351620676 = 2667375^2 + 2435026^2 .

It is an emirp because it is prime and its reverse (10311014244031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13044241011301 - 2³ = 13044241011293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13044241011101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522120505650 + 6522120505651.

It is an arithmetic number, because the mean of its divisors is an integer number (6522120505651).

Almost surely, 2^{13044241011301} is an apocalyptic number.

It is an amenable number.

13044241011301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044241011301 is an equidigital number, since it uses as much as digits as its factorization.

13044241011301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13044241011301 its reverse (10311014244031), we get a palindrome (23355255255332).

The spelling of 13044241011301 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, eleven thousand, three hundred one".