130442410133311 has 2 divisors, whose sum is σ = 130442410133312. Its totient is φ = 130442410133310.

The previous prime is 130442410133309. The next prime is 130442410133339. The reversal of 130442410133311 is 113331014244031.

It is a weak prime.

It is an emirp because it is prime and its reverse (113331014244031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130442410133311 - 2¹ = 130442410133309 is a prime.

It is a super-2 number, since 2×130442410133311² (a number of 29 digits) contains 22 as substring.

Together with 130442410133309, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130442410173311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65221205066655 + 65221205066656.

It is an arithmetic number, because the mean of its divisors is an integer number (65221205066656).

Almost surely, 2^{130442410133311} is an apocalyptic number.

130442410133311 is a deficient number, since it is larger than the sum of its proper divisors (1).

130442410133311 is an equidigital number, since it uses as much as digits as its factorization.

130442410133311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 130442410133311 its reverse (113331014244031), we get a palindrome (243773424377342).

The spelling of 130442410133311 in words is "one hundred thirty trillion, four hundred forty-two billion, four hundred ten million, one hundred thirty-three thousand, three hundred eleven".