13044241401491 has 2 divisors, whose sum is σ = 13044241401492. Its totient is φ = 13044241401490.

The previous prime is 13044241401437. The next prime is 13044241401493. The reversal of 13044241401491 is 19410414244031.

It is a strong prime.

It is an emirp because it is prime and its reverse (19410414244031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13044241401491 - 2¹⁰ = 13044241400467 is a prime.

Together with 13044241401493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13044241401493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522120700745 + 6522120700746.

It is an arithmetic number, because the mean of its divisors is an integer number (6522120700746).

Almost surely, 2^{13044241401491} is an apocalyptic number.

13044241401491 is a deficient number, since it is larger than the sum of its proper divisors (1).

13044241401491 is an equidigital number, since it uses as much as digits as its factorization.

13044241401491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 38.

The spelling of 13044241401491 in words is "thirteen trillion, forty-four billion, two hundred forty-one million, four hundred one thousand, four hundred ninety-one".