130443000520 has 128 divisors (see below), whose sum is σ = 353433600000. Its totient is φ = 42326883072.

The previous prime is 130443000481. The next prime is 130443000521. The reversal of 130443000520 is 25000344031.

It is a junction number, because it is equal to n+sod(n) for n = 130443000491 and 130443000500.

It is not an unprimeable number, because it can be changed into a prime (130443000521) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5515681 + ... + 5539279.

It is an arithmetic number, because the mean of its divisors is an integer number (2761200000).

Almost surely, 2^130443000520 is an apocalyptic number.

130443000520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130443000520, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176716800000).

130443000520 is an abundant number, since it is smaller than the sum of its proper divisors (222990599480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130443000520 is a wasteful number, since it uses less digits than its factorization.

130443000520 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24675 (or 24671 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 130443000520 its reverse (25000344031), we get a palindrome (155443344551).

The spelling of 130443000520 in words is "one hundred thirty billion, four hundred forty-three million, five hundred twenty", and thus it is an aban number.