Base | Representation |
---|---|
bin | 10010111110110110010… |
… | …101100101011000011100 |
3 | 11121200222021002021001001 |
4 | 102332312111211120130 |
5 | 132332440123432030 |
6 | 2435125424000044 |
7 | 163146044526406 |
oct | 22766625453034 |
9 | 4550867067031 |
10 | 1304434202140 |
11 | 463231111963 |
12 | 190984460024 |
13 | 96013973ca4 |
14 | 471c6447b76 |
15 | 23de8367cca |
hex | 12fb656561c |
1304434202140 has 48 divisors (see below), whose sum is σ = 2749898640384. Its totient is φ = 519757819200.
The previous prime is 1304434202111. The next prime is 1304434202153. The reversal of 1304434202140 is 412024344031.
It is a junction number, because it is equal to n+sod(n) for n = 1304434202099 and 1304434202108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37223307 + ... + 37258333.
It is an arithmetic number, because the mean of its divisors is an integer number (57289555008).
Almost surely, 21304434202140 is an apocalyptic number.
1304434202140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1304434202140 is an abundant number, since it is smaller than the sum of its proper divisors (1445464438244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304434202140 is a wasteful number, since it uses less digits than its factorization.
1304434202140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42178 (or 42176 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 1304434202140 its reverse (412024344031), we get a palindrome (1716458546171).
The spelling of 1304434202140 in words is "one trillion, three hundred four billion, four hundred thirty-four million, two hundred two thousand, one hundred forty".
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