Base | Representation |
---|---|
bin | 1011110111010101001001… |
… | …1010111001100110111111 |
3 | 1201012002221022101021011110 |
4 | 2331311102122321212333 |
5 | 3202213031301231000 |
6 | 43424514220253103 |
7 | 2514325115235303 |
oct | 275652232714677 |
9 | 51162838337143 |
10 | 13045198461375 |
11 | 417a48a497803 |
12 | 15682b66a1193 |
13 | 738206a35412 |
14 | 331568b95d03 |
15 | 179507728850 |
hex | bdd526b99bf |
13045198461375 has 64 divisors (see below), whose sum is σ = 23093036748288. Its totient is φ = 6517143360000.
The previous prime is 13045198461311. The next prime is 13045198461413. The reversal of 13045198461375 is 57316489154031.
It is not a de Polignac number, because 13045198461375 - 26 = 13045198461311 is a prime.
It is a hoax number, since the sum of its digits (57) coincides with the sum of the digits of its distinct prime factors.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3503941 + ... + 6194190.
It is an arithmetic number, because the mean of its divisors is an integer number (360828699192).
Almost surely, 213045198461375 is an apocalyptic number.
13045198461375 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13045198461375 is a deficient number, since it is larger than the sum of its proper divisors (10047838286913).
13045198461375 is a wasteful number, since it uses less digits than its factorization.
13045198461375 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9698377 (or 9698367 counting only the distinct ones).
The product of its (nonzero) digits is 10886400, while the sum is 57.
The spelling of 13045198461375 in words is "thirteen trillion, forty-five billion, one hundred ninety-eight million, four hundred sixty-one thousand, three hundred seventy-five".
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