Base | Representation |
---|---|
bin | 111100110000101011… |
… | …0101100011011110111 |
3 | 110110210112120120102012 |
4 | 1321201112230123313 |
5 | 4114211440424012 |
6 | 135535345434435 |
7 | 12266321512631 |
oct | 1714126543367 |
9 | 413715516365 |
10 | 130482358007 |
11 | 50378986911 |
12 | 2135633ba1b |
13 | c3c5ac0881 |
14 | 645b58ba51 |
15 | 35da394622 |
hex | 1e615ac6f7 |
130482358007 has 2 divisors, whose sum is σ = 130482358008. Its totient is φ = 130482358006.
The previous prime is 130482358003. The next prime is 130482358009. The reversal of 130482358007 is 700853284031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130482358007 - 22 = 130482358003 is a prime.
It is a super-3 number, since 3×1304823580073 (a number of 34 digits) contains 333 as substring.
Together with 130482358009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130482358003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65241179003 + 65241179004.
It is an arithmetic number, because the mean of its divisors is an integer number (65241179004).
Almost surely, 2130482358007 is an apocalyptic number.
130482358007 is a deficient number, since it is larger than the sum of its proper divisors (1).
130482358007 is an equidigital number, since it uses as much as digits as its factorization.
130482358007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 41.
The spelling of 130482358007 in words is "one hundred thirty billion, four hundred eighty-two million, three hundred fifty-eight thousand, seven".
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