Base | Representation |
---|---|
bin | 1011110111100001110000… |
… | …0010110011111011111101 |
3 | 1201012102200001111100210212 |
4 | 2331320130002303323331 |
5 | 3202241443233104232 |
6 | 43430234015042205 |
7 | 2514505001456555 |
oct | 275703402637375 |
9 | 51172601440725 |
10 | 13048581144317 |
11 | 4180965975544 |
12 | 1568a9b510365 |
13 | 7386257a7064 |
14 | 3317aa136165 |
15 | 1796546aeeb2 |
hex | bde1c0b3efd |
13048581144317 has 2 divisors, whose sum is σ = 13048581144318. Its totient is φ = 13048581144316.
The previous prime is 13048581144259. The next prime is 13048581144419. The reversal of 13048581144317 is 71344118584031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12428875262521 + 619705881796 = 3525461^2 + 787214^2 .
It is a cyclic number.
It is not a de Polignac number, because 13048581144317 - 220 = 13048580095741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13048581144817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6524290572158 + 6524290572159.
It is an arithmetic number, because the mean of its divisors is an integer number (6524290572159).
Almost surely, 213048581144317 is an apocalyptic number.
It is an amenable number.
13048581144317 is a deficient number, since it is larger than the sum of its proper divisors (1).
13048581144317 is an equidigital number, since it uses as much as digits as its factorization.
13048581144317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1290240, while the sum is 50.
The spelling of 13048581144317 in words is "thirteen trillion, forty-eight billion, five hundred eighty-one million, one hundred forty-four thousand, three hundred seventeen".
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