Base | Representation |
---|---|
bin | 1011110111100001110000… |
… | …0010110011111101100011 |
3 | 1201012102200001111100221122 |
4 | 2331320130002303331203 |
5 | 3202241443233110134 |
6 | 43430234015042455 |
7 | 2514505001460062 |
oct | 275703402637543 |
9 | 51172601440848 |
10 | 13048581144419 |
11 | 4180965975627 |
12 | 1568a9b51042b |
13 | 7386257a7112 |
14 | 3317aa1361d9 |
15 | 1796546b002e |
hex | bde1c0b3f63 |
13048581144419 has 2 divisors, whose sum is σ = 13048581144420. Its totient is φ = 13048581144418.
The previous prime is 13048581144317. The next prime is 13048581144499. The reversal of 13048581144419 is 91444118584031.
It is a strong prime.
It is an emirp because it is prime and its reverse (91444118584031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13048581144419 - 220 = 13048580095843 is a prime.
It is a super-2 number, since 2×130485811444192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13048581144499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6524290572209 + 6524290572210.
It is an arithmetic number, because the mean of its divisors is an integer number (6524290572210).
Almost surely, 213048581144419 is an apocalyptic number.
13048581144419 is a deficient number, since it is larger than the sum of its proper divisors (1).
13048581144419 is an equidigital number, since it uses as much as digits as its factorization.
13048581144419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2211840, while the sum is 53.
The spelling of 13048581144419 in words is "thirteen trillion, forty-eight billion, five hundred eighty-one million, one hundred forty-four thousand, four hundred nineteen".
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