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13049374431680 = 2657113113213319
BaseRepresentation
bin1011110111100100101101…
…0100111101100111000000
31201012111201100012112111022
42331321023110331213000
53202300104323303210
643430444434005012
72514533443344656
oct275711324754700
951174640175438
1013049374431680
114181232741034
121569081116768
13738720c49772
14331843634dd6
1517969e15d155
hexbde4b53d9c0

13049374431680 has 224 divisors, whose sum is σ = 31785638353920. Its totient is φ = 5101544448000.

The previous prime is 13049374431631. The next prime is 13049374431727. The reversal of 13049374431680 is 8613447394031.

It is a Smith number, since the sum of its digits (53) coincides with the sum of the digits of its prime factors.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3931717061 + ... + 3931720379.

Almost surely, 213049374431680 is an apocalyptic number.

13049374431680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13049374431680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15892819176960).

13049374431680 is an abundant number, since it is smaller than the sum of its proper divisors (18736263922240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13049374431680 is a wasteful number, since it uses less digits than its factorization.

13049374431680 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4859 (or 4849 counting only the distinct ones).

The product of its (nonzero) digits is 5225472, while the sum is 53.

The spelling of 13049374431680 in words is "thirteen trillion, forty-nine billion, three hundred seventy-four million, four hundred thirty-one thousand, six hundred eighty".