Base | Representation |
---|---|
bin | 111100110001001101… |
… | …1111100101011111011 |
3 | 110110211210201220201002 |
4 | 1321202123330223323 |
5 | 4114231112400012 |
6 | 135541234515215 |
7 | 12266632024331 |
oct | 1714233745373 |
9 | 413753656632 |
10 | 130500512507 |
11 | 50388156632 |
12 | 21360435b0b |
13 | c3c97a8c91 |
14 | 645db55b51 |
15 | 35dbc7d7c2 |
hex | 1e626fcafb |
130500512507 has 2 divisors, whose sum is σ = 130500512508. Its totient is φ = 130500512506.
The previous prime is 130500512479. The next prime is 130500512509. The reversal of 130500512507 is 705215005031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130500512507 - 228 = 130232077051 is a prime.
Together with 130500512509, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130500512507.
It is not a weakly prime, because it can be changed into another prime (130500512509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65250256253 + 65250256254.
It is an arithmetic number, because the mean of its divisors is an integer number (65250256254).
Almost surely, 2130500512507 is an apocalyptic number.
130500512507 is a deficient number, since it is larger than the sum of its proper divisors (1).
130500512507 is an equidigital number, since it uses as much as digits as its factorization.
130500512507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5250, while the sum is 29.
Adding to 130500512507 its reverse (705215005031), we get a palindrome (835715517538).
The spelling of 130500512507 in words is "one hundred thirty billion, five hundred million, five hundred twelve thousand, five hundred seven".
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