Base | Representation |
---|---|
bin | 10010111111100110011… |
… | …100110101111001010001 |
3 | 11121210001111222201122011 |
4 | 102333212130311321101 |
5 | 132341113300124103 |
6 | 2435341501142521 |
7 | 163205045636431 |
oct | 22774634657121 |
9 | 4553044881564 |
10 | 1305241411153 |
11 | 463605826a49 |
12 | 190b6a85aa41 |
13 | 96111c7c264 |
14 | 4726172c2c1 |
15 | 23e44165d6d |
hex | 12fe6735e51 |
1305241411153 has 2 divisors, whose sum is σ = 1305241411154. Its totient is φ = 1305241411152.
The previous prime is 1305241411151. The next prime is 1305241411171. The reversal of 1305241411153 is 3511141425031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1117815623824 + 187425787329 = 1057268^2 + 432927^2 .
It is an emirp because it is prime and its reverse (3511141425031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1305241411153 - 21 = 1305241411151 is a prime.
Together with 1305241411151, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1305241411151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652620705576 + 652620705577.
It is an arithmetic number, because the mean of its divisors is an integer number (652620705577).
Almost surely, 21305241411153 is an apocalyptic number.
It is an amenable number.
1305241411153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305241411153 is an equidigital number, since it uses as much as digits as its factorization.
1305241411153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1305241411153 its reverse (3511141425031), we get a palindrome (4816382836184).
The spelling of 1305241411153 in words is "one trillion, three hundred five billion, two hundred forty-one million, four hundred eleven thousand, one hundred fifty-three".
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