Base | Representation |
---|---|
bin | 10010111111101010101… |
… | …011010101111001111111 |
3 | 11121210020110102022212101 |
4 | 102333222223111321333 |
5 | 132341234423234101 |
6 | 2435352513045531 |
7 | 163206566443216 |
oct | 22775253257177 |
9 | 4553213368771 |
10 | 1305312321151 |
11 | 463641859753 |
12 | 190b8a5568a7 |
13 | 96123879037 |
14 | 4726ad0a07d |
15 | 23e4a4c1401 |
hex | 12feaad5e7f |
1305312321151 has 2 divisors, whose sum is σ = 1305312321152. Its totient is φ = 1305312321150.
The previous prime is 1305312321149. The next prime is 1305312321161. The reversal of 1305312321151 is 1511232135031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1305312321151 - 21 = 1305312321149 is a prime.
It is a super-2 number, since 2×13053123211512 (a number of 25 digits) contains 22 as substring.
Together with 1305312321149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305312321161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652656160575 + 652656160576.
It is an arithmetic number, because the mean of its divisors is an integer number (652656160576).
Almost surely, 21305312321151 is an apocalyptic number.
1305312321151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305312321151 is an equidigital number, since it uses as much as digits as its factorization.
1305312321151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 1305312321151 its reverse (1511232135031), we get a palindrome (2816544456182).
The spelling of 1305312321151 in words is "one trillion, three hundred five billion, three hundred twelve million, three hundred twenty-one thousand, one hundred fifty-one".
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