Base | Representation |
---|---|
bin | 11000010100001010… |
… | …10001001001100011 |
3 | 1020200202111200222221 |
4 | 30022011101021203 |
5 | 203213314230021 |
6 | 5555201411511 |
7 | 641330431264 |
oct | 141205211143 |
9 | 36622450887 |
10 | 13054055011 |
11 | 5599745818 |
12 | 2643939b97 |
13 | 1300649a0a |
14 | 8bb9da96b |
15 | 51607d241 |
hex | 30a151263 |
13054055011 has 2 divisors, whose sum is σ = 13054055012. Its totient is φ = 13054055010.
The previous prime is 13054054987. The next prime is 13054055029. The reversal of 13054055011 is 11055045031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13054055011 - 215 = 13054022243 is a prime.
It is not a weakly prime, because it can be changed into another prime (13054055071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527027505 + 6527027506.
It is an arithmetic number, because the mean of its divisors is an integer number (6527027506).
Almost surely, 213054055011 is an apocalyptic number.
13054055011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13054055011 is an equidigital number, since it uses as much as digits as its factorization.
13054055011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1500, while the sum is 25.
The spelling of 13054055011 in words is "thirteen billion, fifty-four million, fifty-five thousand, eleven".
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