1305440400013 has 2 divisors, whose sum is σ = 1305440400014. Its totient is φ = 1305440400012.

The previous prime is 1305440399969. The next prime is 1305440400029. The reversal of 1305440400013 is 3100040445031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 956096751204 + 349343648809 = 977802^2 + 591053^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1305440400013 is a prime.

It is a super-2 number, since 2×1305440400013² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305440400613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652720200006 + 652720200007.

It is an arithmetic number, because the mean of its divisors is an integer number (652720200007).

Almost surely, 2^{1305440400013} is an apocalyptic number.

It is an amenable number.

1305440400013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305440400013 is an equidigital number, since it uses as much as digits as its factorization.

1305440400013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1305440400013 its reverse (3100040445031), we get a palindrome (4405480845044).

The spelling of 1305440400013 in words is "one trillion, three hundred five billion, four hundred forty million, four hundred thousand, thirteen".