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1305445403117 is a prime number
BaseRepresentation
bin10010111111110010100…
…111000000100111101101
311121210120201211121000002
4102333302213000213231
5132342023010344432
62435414025314045
7163213103561252
oct22776247004755
94553521747002
101305445403117
114636aa996149
12191007035925
139614530356b
144728086d429
1523e5700ce62
hex12ff29c09ed

1305445403117 has 2 divisors, whose sum is σ = 1305445403118. Its totient is φ = 1305445403116.

The previous prime is 1305445403077. The next prime is 1305445403149. The reversal of 1305445403117 is 7113045445031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1232690590756 + 72754812361 = 1110266^2 + 269731^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1305445403117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305445403917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652722701558 + 652722701559.

It is an arithmetic number, because the mean of its divisors is an integer number (652722701559).

Almost surely, 21305445403117 is an apocalyptic number.

It is an amenable number.

1305445403117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305445403117 is an equidigital number, since it uses as much as digits as its factorization.

1305445403117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 1305445403117 in words is "one trillion, three hundred five billion, four hundred forty-five million, four hundred three thousand, one hundred seventeen".