Base | Representation |
---|---|
bin | 111100110010110000… |
… | …1000111101101101111 |
3 | 110110222101222220200102 |
4 | 1321211201013231233 |
5 | 4114332330400142 |
6 | 135550322421315 |
7 | 12301130251013 |
oct | 1714541075557 |
9 | 413871886612 |
10 | 130552200047 |
11 | 5040434a205 |
12 | 2137580183b |
13 | c407405519 |
14 | 646696c543 |
15 | 35e158d532 |
hex | 1e65847b6f |
130552200047 has 2 divisors, whose sum is σ = 130552200048. Its totient is φ = 130552200046.
The previous prime is 130552199989. The next prime is 130552200071. The reversal of 130552200047 is 740002255031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130552200047 - 212 = 130552195951 is a prime.
It is a super-2 number, since 2×1305522000472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130552199992 and 130552200019.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130552202047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276100023 + 65276100024.
It is an arithmetic number, because the mean of its divisors is an integer number (65276100024).
Almost surely, 2130552200047 is an apocalyptic number.
130552200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
130552200047 is an equidigital number, since it uses as much as digits as its factorization.
130552200047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 29.
Adding to 130552200047 its reverse (740002255031), we get a palindrome (870554455078).
The spelling of 130552200047 in words is "one hundred thirty billion, five hundred fifty-two million, two hundred thousand, forty-seven".
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