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130553217637 is a prime number
BaseRepresentation
bin111100110010110010…
…1000000001001100101
3110110222110220121112221
41321211211000021211
54114333110431022
6135550400312341
712301142016523
oct1714545001145
9413873817487
10130553217637
1150404984797
12213760126b1
13c4076a074b
146466b55313
1535e16decc7
hex1e65940265

130553217637 has 2 divisors, whose sum is σ = 130553217638. Its totient is φ = 130553217636.

The previous prime is 130553217631. The next prime is 130553217643. The reversal of 130553217637 is 736712355031.

It is a balanced prime because it is at equal distance from previous prime (130553217631) and next prime (130553217643).

It can be written as a sum of positive squares in only one way, i.e., 78239921796 + 52313295841 = 279714^2 + 228721^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130553217637 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130553217593 and 130553217602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130553217631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276608818 + 65276608819.

It is an arithmetic number, because the mean of its divisors is an integer number (65276608819).

Almost surely, 2130553217637 is an apocalyptic number.

It is an amenable number.

130553217637 is a deficient number, since it is larger than the sum of its proper divisors (1).

130553217637 is an equidigital number, since it uses as much as digits as its factorization.

130553217637 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 396900, while the sum is 43.

The spelling of 130553217637 in words is "one hundred thirty billion, five hundred fifty-three million, two hundred seventeen thousand, six hundred thirty-seven".