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130554119 is a prime number
BaseRepresentation
bin1111100100000…
…01100100000111
3100002122211120202
413302001210013
5231410212434
620542121115
73143456153
oct762014407
9302584522
10130554119
1167770273
123788019b
1321080a77
14134a6063
15b6dca7e
hex7c81907

130554119 has 2 divisors, whose sum is σ = 130554120. Its totient is φ = 130554118.

The previous prime is 130554107. The next prime is 130554121. The reversal of 130554119 is 911455031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130554119 is a prime.

It is a super-2 number, since 2×1305541192 = 34088755975732322, which contains 22 as substring.

Together with 130554121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130554091 and 130554100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130554419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65277059 + 65277060.

It is an arithmetic number, because the mean of its divisors is an integer number (65277060).

Almost surely, 2130554119 is an apocalyptic number.

130554119 is a deficient number, since it is larger than the sum of its proper divisors (1).

130554119 is an equidigital number, since it uses as much as digits as its factorization.

130554119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 29.

The square root of 130554119 is about 11426.0281375463. The cubic root of 130554119 is about 507.2984392134.

The spelling of 130554119 in words is "one hundred thirty million, five hundred fifty-four thousand, one hundred nineteen".