Base | Representation |
---|---|
bin | 111100110010110100… |
… | …1001011011101001011 |
3 | 110110222112222020110021 |
4 | 1321211221023131023 |
5 | 4114333401000043 |
6 | 135550440001311 |
7 | 12301154226565 |
oct | 1714551133513 |
9 | 413875866407 |
10 | 130554312523 |
11 | 50405562358 |
12 | 21376460237 |
13 | c407994bcb |
14 | 6466d5c335 |
15 | 35e18593ed |
hex | 1e65a4b74b |
130554312523 has 2 divisors, whose sum is σ = 130554312524. Its totient is φ = 130554312522.
The previous prime is 130554312509. The next prime is 130554312781. The reversal of 130554312523 is 325213455031.
It is a weak prime.
It is an emirp because it is prime and its reverse (325213455031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130554312523 - 29 = 130554312011 is a prime.
It is not a weakly prime, because it can be changed into another prime (130554312503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65277156261 + 65277156262.
It is an arithmetic number, because the mean of its divisors is an integer number (65277156262).
Almost surely, 2130554312523 is an apocalyptic number.
130554312523 is a deficient number, since it is larger than the sum of its proper divisors (1).
130554312523 is an equidigital number, since it uses as much as digits as its factorization.
130554312523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 130554312523 its reverse (325213455031), we get a palindrome (455767767554).
The spelling of 130554312523 in words is "one hundred thirty billion, five hundred fifty-four million, three hundred twelve thousand, five hundred twenty-three".
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