Base | Representation |
---|---|
bin | 111100110011000111… |
… | …1000100000001111001 |
3 | 110111000020122210022002 |
4 | 1321212033010001321 |
5 | 4114343421243302 |
6 | 135551432510345 |
7 | 12301334521235 |
oct | 1714617040171 |
9 | 414006583262 |
10 | 130564243577 |
11 | 50410125739 |
12 | 2137984b3b5 |
13 | c409a61281 |
14 | 64683c55c5 |
15 | 35e266bc02 |
hex | 1e663c4079 |
130564243577 has 2 divisors, whose sum is σ = 130564243578. Its totient is φ = 130564243576.
The previous prime is 130564243571. The next prime is 130564243619. The reversal of 130564243577 is 775342465031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101570327401 + 28993916176 = 318701^2 + 170276^2 .
It is a cyclic number.
It is not a de Polignac number, because 130564243577 - 24 = 130564243561 is a prime.
It is not a weakly prime, because it can be changed into another prime (130564243571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65282121788 + 65282121789.
It is an arithmetic number, because the mean of its divisors is an integer number (65282121789).
Almost surely, 2130564243577 is an apocalyptic number.
It is an amenable number.
130564243577 is a deficient number, since it is larger than the sum of its proper divisors (1).
130564243577 is an equidigital number, since it uses as much as digits as its factorization.
130564243577 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 47.
The spelling of 130564243577 in words is "one hundred thirty billion, five hundred sixty-four million, two hundred forty-three thousand, five hundred seventy-seven".
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