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130565839981 is a prime number
BaseRepresentation
bin111100110011001010…
…1001001110001101101
3110111000100122220011011
41321212111021301231
54114344323334411
6135551531025221
712301354220413
oct1714625116155
9414010586134
10130565839981
1150411016085
122137a29b211
13c40a19caa5
1464686bd2b3
1535e2884c21
hex1e66549c6d

130565839981 has 2 divisors, whose sum is σ = 130565839982. Its totient is φ = 130565839980.

The previous prime is 130565839979. The next prime is 130565840017. The reversal of 130565839981 is 189938565031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86409542025 + 44156297956 = 293955^2 + 210134^2 .

It is an emirp because it is prime and its reverse (189938565031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130565839981 - 21 = 130565839979 is a prime.

It is a super-5 number, since 5×1305658399815 (a number of 57 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

Together with 130565839979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130565839951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65282919990 + 65282919991.

It is an arithmetic number, because the mean of its divisors is an integer number (65282919991).

Almost surely, 2130565839981 is an apocalyptic number.

It is an amenable number.

130565839981 is a deficient number, since it is larger than the sum of its proper divisors (1).

130565839981 is an equidigital number, since it uses as much as digits as its factorization.

130565839981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 58.

The spelling of 130565839981 in words is "one hundred thirty billion, five hundred sixty-five million, eight hundred thirty-nine thousand, nine hundred eighty-one".