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13059483653 is a prime number
BaseRepresentation
bin11000010100110011…
…11110100000000101
31020201010201111200202
430022121332200011
5203221211434103
65555514020245
7641424531236
oct141231764005
936633644622
1013059483653
1155a18133a7
122645717685
1313017ca928
148bc61108d
155167a1988
hex30a67e805

13059483653 has 2 divisors, whose sum is σ = 13059483654. Its totient is φ = 13059483652.

The previous prime is 13059483607. The next prime is 13059483707. The reversal of 13059483653 is 35638495031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10378108129 + 2681375524 = 101873^2 + 51782^2 .

It is a cyclic number.

It is not a de Polignac number, because 13059483653 - 218 = 13059221509 is a prime.

It is a super-2 number, since 2×130594836532 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13059483598 and 13059483607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13059483953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6529741826 + 6529741827.

It is an arithmetic number, because the mean of its divisors is an integer number (6529741827).

Almost surely, 213059483653 is an apocalyptic number.

It is an amenable number.

13059483653 is a deficient number, since it is larger than the sum of its proper divisors (1).

13059483653 is an equidigital number, since it uses as much as digits as its factorization.

13059483653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1166400, while the sum is 47.

The spelling of 13059483653 in words is "thirteen billion, fifty-nine million, four hundred eighty-three thousand, six hundred fifty-three".