Base | Representation |
---|---|
bin | 10011000000010011000… |
… | …110010110101011000111 |
3 | 11121211222201111220202122 |
4 | 103000103012112223013 |
5 | 132344132031201243 |
6 | 2435544100400155 |
7 | 163232443003244 |
oct | 23002306265307 |
9 | 4554881456678 |
10 | 1305990490823 |
11 | 46395a648657 |
12 | 1911396a605b |
13 | 96201213b75 |
14 | 472d30005cb |
15 | 23e89cd0668 |
hex | 13013196ac7 |
1305990490823 has 2 divisors, whose sum is σ = 1305990490824. Its totient is φ = 1305990490822.
The previous prime is 1305990490787. The next prime is 1305990490873. The reversal of 1305990490823 is 3280940995031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1305990490823 - 26 = 1305990490759 is a prime.
It is a super-2 number, since 2×13059904908232 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305990490873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652995245411 + 652995245412.
It is an arithmetic number, because the mean of its divisors is an integer number (652995245412).
Almost surely, 21305990490823 is an apocalyptic number.
1305990490823 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305990490823 is an equidigital number, since it uses as much as digits as its factorization.
1305990490823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2099520, while the sum is 53.
The spelling of 1305990490823 in words is "one trillion, three hundred five billion, nine hundred ninety million, four hundred ninety thousand, eight hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.378 sec. • engine limits •