Base | Representation |
---|---|
bin | 1011111000001100011100… |
… | …1111101010000101000110 |
3 | 1201020112020212122202111221 |
4 | 2332003013033222011012 |
5 | 3202433432044202332 |
6 | 43435411233550554 |
7 | 2515362022560052 |
oct | 276030717520506 |
9 | 51215225582457 |
10 | 13060043350342 |
11 | 4185807aa658a |
12 | 156b15a11545a |
13 | 7397313b30a1 |
14 | 332176560c62 |
15 | 179ac5aee297 |
hex | be0c73ea146 |
13060043350342 has 32 divisors (see below), whose sum is σ = 20512512244224. Its totient is φ = 6224513064000.
The previous prime is 13060043350309. The next prime is 13060043350351. The reversal of 13060043350342 is 24305334006031.
13060043350342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13060043350298 and 13060043350307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59990853 + ... + 60208159.
It is an arithmetic number, because the mean of its divisors is an integer number (641016007632).
Almost surely, 213060043350342 is an apocalyptic number.
13060043350342 is a deficient number, since it is larger than the sum of its proper divisors (7452468893882).
13060043350342 is a wasteful number, since it uses less digits than its factorization.
13060043350342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221844.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 13060043350342 its reverse (24305334006031), we get a palindrome (37365377356373).
The spelling of 13060043350342 in words is "thirteen trillion, sixty billion, forty-three million, three hundred fifty thousand, three hundred forty-two".
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