Base | Representation |
---|---|
bin | 111100110100100110… |
… | …0111011000110001111 |
3 | 110111010201022101222002 |
4 | 1321221030323012033 |
5 | 4114444141424401 |
6 | 140000411342515 |
7 | 12302510542442 |
oct | 1715114730617 |
9 | 414121271862 |
10 | 130614014351 |
11 | 5043622a207 |
12 | 21392451a3b |
13 | c417169232 |
14 | 6470c5d659 |
15 | 35e6beda6b |
hex | 1e6933b18f |
130614014351 has 2 divisors, whose sum is σ = 130614014352. Its totient is φ = 130614014350.
The previous prime is 130614014291. The next prime is 130614014353. The reversal of 130614014351 is 153410416031.
It is a strong prime.
It is an emirp because it is prime and its reverse (153410416031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130614014351 - 226 = 130546905487 is a prime.
It is a super-3 number, since 3×1306140143513 (a number of 34 digits) contains 333 as substring.
It is a Sophie Germain prime.
Together with 130614014353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130614014353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65307007175 + 65307007176.
It is an arithmetic number, because the mean of its divisors is an integer number (65307007176).
Almost surely, 2130614014351 is an apocalyptic number.
130614014351 is a deficient number, since it is larger than the sum of its proper divisors (1).
130614014351 is an equidigital number, since it uses as much as digits as its factorization.
130614014351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 130614014351 in words is "one hundred thirty billion, six hundred fourteen million, fourteen thousand, three hundred fifty-one".
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