Base | Representation |
---|---|
bin | 11000010101000110… |
… | …01011011000010111 |
3 | 1020201022021001101221 |
4 | 30022203023120113 |
5 | 203222321130303 |
6 | 10000041431211 |
7 | 641454165403 |
oct | 141243133027 |
9 | 36638231357 |
10 | 13061895703 |
11 | 55a311062a |
12 | 264649b507 |
13 | 130216378c |
14 | 8bca7c103 |
15 | 516acb4bd |
hex | 30a8cb617 |
13061895703 has 2 divisors, whose sum is σ = 13061895704. Its totient is φ = 13061895702.
The previous prime is 13061895701. The next prime is 13061895727. The reversal of 13061895703 is 30759816031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13061895703 - 21 = 13061895701 is a prime.
It is a super-2 number, since 2×130618957032 (a number of 21 digits) contains 22 as substring.
Together with 13061895701, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13061895703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13061895701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530947851 + 6530947852.
It is an arithmetic number, because the mean of its divisors is an integer number (6530947852).
Almost surely, 213061895703 is an apocalyptic number.
13061895703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13061895703 is an equidigital number, since it uses as much as digits as its factorization.
13061895703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 13061895703 in words is "thirteen billion, sixty-one million, eight hundred ninety-five thousand, seven hundred three".
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