Base | Representation |
---|---|
bin | 100110111011110… |
… | …0001010101101111 |
3 | 10101001020000001022 |
4 | 1031313201111233 |
5 | 10133414300421 |
6 | 333344404355 |
7 | 44242134452 |
oct | 11567412557 |
9 | 3331200038 |
10 | 1306400111 |
11 | 610479815 |
12 | 3056166bb |
13 | 17a869123 |
14 | c5709499 |
15 | 79a567ab |
hex | 4dde156f |
1306400111 has 2 divisors, whose sum is σ = 1306400112. Its totient is φ = 1306400110.
The previous prime is 1306400101. The next prime is 1306400113. The reversal of 1306400111 is 1110046031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1306400111 is a prime.
Together with 1306400113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1306400111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1306400113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653200055 + 653200056.
It is an arithmetic number, because the mean of its divisors is an integer number (653200056).
Almost surely, 21306400111 is an apocalyptic number.
1306400111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1306400111 is an equidigital number, since it uses as much as digits as its factorization.
1306400111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
The square root of 1306400111 is about 36144.1573563418. The cubic root of 1306400111 is about 1093.1809866571.
Adding to 1306400111 its reverse (1110046031), we get a palindrome (2416446142).
The spelling of 1306400111 in words is "one billion, three hundred six million, four hundred thousand, one hundred eleven".
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