Base | Representation |
---|---|
bin | 1011111000100111110110… |
… | …1111011100110001010111 |
3 | 1201021020020120200121202102 |
4 | 2332021331233130301113 |
5 | 3203044013411330142 |
6 | 43443025234432315 |
7 | 2516042233135361 |
oct | 276117557346127 |
9 | 51236216617672 |
10 | 13067400105047 |
11 | 4188942769252 |
12 | 1570671a3269b |
13 | 73a334598892 |
14 | 332673625d31 |
15 | 179da68d8532 |
hex | be27dbdcc57 |
13067400105047 has 2 divisors, whose sum is σ = 13067400105048. Its totient is φ = 13067400105046.
The previous prime is 13067400105041. The next prime is 13067400105077. The reversal of 13067400105047 is 74050100476031.
It is a weak prime.
It is an emirp because it is prime and its reverse (74050100476031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13067400105047 - 222 = 13067395910743 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13067400105047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13067400105041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6533700052523 + 6533700052524.
It is an arithmetic number, because the mean of its divisors is an integer number (6533700052524).
Almost surely, 213067400105047 is an apocalyptic number.
13067400105047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13067400105047 is an equidigital number, since it uses as much as digits as its factorization.
13067400105047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70560, while the sum is 38.
The spelling of 13067400105047 in words is "thirteen trillion, sixty-seven billion, four hundred million, one hundred five thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •