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130725557212517 is a prime number
BaseRepresentation
bin11101101110010011101010…
…011001101001010101100101
3122010212020111211220121012022
4131232103222121221111211
5114113301420121300032
61142010254131032525
736351416113230611
oct3556235231512545
9563766454817168
10130725557212517
1138720441046963
12127b35a473b745
1357c34a0822987
14243d217856341
15101a7121dd512
hex76e4ea669565

130725557212517 has 2 divisors, whose sum is σ = 130725557212518. Its totient is φ = 130725557212516.

The previous prime is 130725557212513. The next prime is 130725557212609. The reversal of 130725557212517 is 715212755527031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128969320009156 + 1756237203361 = 11356466^2 + 1325231^2 .

It is a cyclic number.

It is not a de Polignac number, because 130725557212517 - 22 = 130725557212513 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130725557212513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65362778606258 + 65362778606259.

It is an arithmetic number, because the mean of its divisors is an integer number (65362778606259).

Almost surely, 2130725557212517 is an apocalyptic number.

It is an amenable number.

130725557212517 is a deficient number, since it is larger than the sum of its proper divisors (1).

130725557212517 is an equidigital number, since it uses as much as digits as its factorization.

130725557212517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5145000, while the sum is 53.

The spelling of 130725557212517 in words is "one hundred thirty trillion, seven hundred twenty-five billion, five hundred fifty-seven million, two hundred twelve thousand, five hundred seventeen".