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1309645333253 is a prime number
BaseRepresentation
bin10011000011101100111…
…100011110001100000101
311122012102102202011001002
4103003230330132030011
5132424123201131003
62441350500343045
7163422142441445
oct23035474361405
94565372664032
101309645333253
11465465714894
121919996a4a85
139666448651a
144755c588125
1524100ac6a88
hex130ecf1e305

1309645333253 has 2 divisors, whose sum is σ = 1309645333254. Its totient is φ = 1309645333252.

The previous prime is 1309645333207. The next prime is 1309645333273. The reversal of 1309645333253 is 3523335469031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 989869786084 + 319775547169 = 994922^2 + 565487^2 .

It is a cyclic number.

It is not a de Polignac number, because 1309645333253 - 28 = 1309645332997 is a prime.

It is a super-2 number, since 2×13096453332532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1309645333198 and 1309645333207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1309645333273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654822666626 + 654822666627.

It is an arithmetic number, because the mean of its divisors is an integer number (654822666627).

Almost surely, 21309645333253 is an apocalyptic number.

It is an amenable number.

1309645333253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1309645333253 is an equidigital number, since it uses as much as digits as its factorization.

1309645333253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2624400, while the sum is 47.

The spelling of 1309645333253 in words is "one trillion, three hundred nine billion, six hundred forty-five million, three hundred thirty-three thousand, two hundred fifty-three".