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130994501702413 is a prime number
BaseRepresentation
bin11101110010001110001000…
…101111011101001100001101
3122011210221201001102020220111
4131302032020233131030031
5114132203214413434123
61142334013204520021
736410016603536416
oct3562161057351415
9564727631366814
10130994501702413
1138814502211828
12128377416b0011
1358129616b4bab
14244c24c2b280d
15102270327990d
hex772388bdd30d

130994501702413 has 2 divisors, whose sum is σ = 130994501702414. Its totient is φ = 130994501702412.

The previous prime is 130994501702387. The next prime is 130994501702419. The reversal of 130994501702413 is 314207105499031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111955085059689 + 19039416642724 = 10580883^2 + 4363418^2 .

It is a cyclic number.

It is not a de Polignac number, because 130994501702413 - 25 = 130994501702381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130994501702419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65497250851206 + 65497250851207.

It is an arithmetic number, because the mean of its divisors is an integer number (65497250851207).

Almost surely, 2130994501702413 is an apocalyptic number.

It is an amenable number.

130994501702413 is a deficient number, since it is larger than the sum of its proper divisors (1).

130994501702413 is an equidigital number, since it uses as much as digits as its factorization.

130994501702413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 816480, while the sum is 49.

The spelling of 130994501702413 in words is "one hundred thirty trillion, nine hundred ninety-four billion, five hundred one million, seven hundred two thousand, four hundred thirteen".