Base | Representation |
---|---|
bin | 11101110010010011010000… |
… | …100001111111111000100111 |
3 | 122011211110220022111200000122 |
4 | 131302103100201333320213 |
5 | 114132301000240220401 |
6 | 1142340323020032155 |
7 | 36410303101625444 |
oct | 3562232041777047 |
9 | 564743808450018 |
10 | 131000001101351 |
11 | 38816874505628 |
12 | 1283881739265b |
13 | 5813329b480c5 |
14 | 244c6108109cb |
15 | 1022925e7b21b |
hex | 7724d087fe27 |
131000001101351 has 2 divisors, whose sum is σ = 131000001101352. Its totient is φ = 131000001101350.
The previous prime is 131000001101269. The next prime is 131000001101357. The reversal of 131000001101351 is 153101100000131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131000001101351 is a prime.
It is a super-2 number, since 2×1310000011013512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131000001101357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500000550675 + 65500000550676.
It is an arithmetic number, because the mean of its divisors is an integer number (65500000550676).
Almost surely, 2131000001101351 is an apocalyptic number.
131000001101351 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000001101351 is an equidigital number, since it uses as much as digits as its factorization.
131000001101351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 17.
Adding to 131000001101351 its reverse (153101100000131), we get a palindrome (284101101101482).
The spelling of 131000001101351 in words is "one hundred thirty-one trillion, one million, one hundred one thousand, three hundred fifty-one".
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