131000041200000 has 1536 divisors, whose sum is σ = 518866290432000. Its totient is φ = 28648488960000.

The previous prime is 131000041199999. The next prime is 131000041200001. The reversal of 131000041200000 is 2140000131.

It is a happy number.

131000041200000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (131000041199999) and next prime (131000041200001).

It is a super-2 number, since 2×131000041200000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000041200001) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 27526797621 + ... + 27526802379.

It is an arithmetic number, because the mean of its divisors is an integer number (337803574500).

Almost surely, 2^{131000041200000} is an apocalyptic number.

131000041200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000041200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (259433145216000).

131000041200000 is an abundant number, since it is smaller than the sum of its proper divisors (387866249232000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000041200000 is an equidigital number, since it uses as much as digits as its factorization.

131000041200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4950 (or 4918 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 131000041200000 its reverse (2140000131), we get a palindrome (131002181200131).

The spelling of 131000041200000 in words is "one hundred thirty-one trillion, forty-one million, two hundred thousand".